x4 + y4 = 1
squircle forumula
squircle with equal radii of 1 and center at the origin
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esoteric math stuff
x4 + y4 = 1
√2 √2 √i = - -- - -- i 2 2
√2 √2 √i = -- + -- i 2 2
b^m/n = (n√b)^m
8^2/3 = (3√8)^2 = 2 ^2 = 4
27^x = 81
3^3x = 3^4 3x = 4 x = 4/3
27^4/3 = (3√27)^4 = 3^4 = 81
n!--------(n - k)!
combinations: order doesn't matter, so divide by the number of redundant results, which is k! n!-------------(n - k)! * k!
5 * last (y) + the rest (x)
or the rest (x) - 2 * last (y)
10x + y 50x + 5y = (x + 5y) + 49x 49x is divisible by 7 so only need to test x + 5y x + 5yx - 2y
augend 5 addend 2 sum…